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14-09-2017
Mathematics

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Find the equation of the circle whose center is at (4, 5) and that contains (13, −1).

Respuesta :

14-09-2017

the equation of circle is
(x-4)^2+(y-5)^2=R^2
if you replace the (13, -1) with x and y the R^2 will be 117
(x-4)^2+(y-5)^2=117

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