Respuesta :
Answer: Approx 316.228 times
Step-by-step explanation:
Let [tex]I_1[/tex] be the intensity of the earthquake in Chile
And, [tex]I_2[/tex] be the intensity of the earthquake in Haiti,
Since, Haiti was hit by a earthquake which registered at 7.0 on the Richter scale and Chile was hit by a earthquake which registered at 9.5 on the Richter scale,
Thus, for Chile,
[tex]9.5 = log (\frac{I_1}{I_0} )[/tex] --------(1) [ by the formula, [tex]R = log (\frac{I}{I_0} )[/tex] ]
And, For Haiti,
[tex]7 = log (\frac{I_2}{I_0} )[/tex] ----------(2),
Equation (1) - Equation (1),
[tex]2.5 = log (\frac{I_1}{I_0} )-log (\frac{I_2}{I_0} )[/tex]
⇒ [tex]2.5 = log(\frac{I_1}{I_2} )[/tex]
⇒ [tex]10^{2.5} = \frac{I_1}{I_2}[/tex]
⇒ [tex]10^{2.5} = \frac{I_1}{I_2}[/tex]
⇒ [tex]316.227766017 I_2=I_1[/tex]
That is, the Intensity of Chile is approx 316.228 times of intensity of Haiti.
It should be noted that the times greater that the intensity of the Chilean earthquake was is 316.228 times.
How to calculate the earthquake intensity
From the information, Haiti was hit by a devastating earthquake which registered at 7.0 on the Richter scale an recorded earthquake in chile was at 9.5 on the Richter scale.
Based on the information, the intensity will be calculated thus:
2.5 = log(I1 / I2)
Then, the intensity will be 10 raise to the power of 2.5 which will be 316.228.
Learn more about earthquakes on:
https://brainly.com/question/248561
