Lightskin15 Lightskin15

12-08-2015
Mathematics

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How do you solve the linear equations y=2x-3 and 4y=2x+8

Respuesta :

12-08-2015

Subtract the first equation from the second to get:

4y-y=2x-2x+8+3

Simplifying, we see that 3y=11, so y=11/3. Substituting this into the first equation, we have:

11/3=2x-3

Adding 3, we see that 2x=20/3, so x=10/3.

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