donf7160 donf7160
  • 12-10-2017
  • Physics
contestada

It takes 3.3 j of work to stretch a hooke's-law spring 15 cm from its unstressed length. how much the extra work is required to stretch it an additional 11.3 cm? answer in units of j.

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cashstar30oxvkuu
cashstar30oxvkuu cashstar30oxvkuu
  • 15-10-2017
5.786j

Set up a proportion. Add 11.3 and 15=26.3cm.
Next, the proportion of 3.3j/15cm=×/26.3cm
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