KEITH555 KEITH555

11-11-2017
Mathematics

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use distributive law to factor 3+27b+6c check by multiplying

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Аноним Аноним

11-11-2017

[tex]3+27b+6c[/tex]

[tex]GCF = 3[/tex]

[tex]3( \dfrac{3}{3} + \dfrac{27b}{3} + \dfrac{6c}{3}) [/tex] [tex]\text{Factor out the GCF}[/tex]

[tex]3(1+9b+2c) [/tex] [tex]\text{Simplify each term in parentheses}[/tex]

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