[tex](2x^2 = -8x + 45) \\ \\ 2x^2 + 8x - 45 = 0 \\ \\ x = \frac{-8+2 \sqrt{106} }{4} , \frac{-8-2 \sqrt{106} }{4} \\ \\ x = - \frac{4- \sqrt{106} }{2} , - \frac{4+ \sqrt{106} }{2} \\ \\ Answer: x = - \frac{4- \sqrt{106} }{2} , - \frac{4+ \sqrt{106} }{2} [/tex]
