There's 3 possibilities for a rectangle with an area of 32 square feet.
[tex]8 \times 4 \\ 16 \times 2 \\ 32 \times 1[/tex]
If 8 x 4, Perimeter =
[tex]2(8) + 2(4) = 24[/tex]
If 16 x 2, Perimeter =
[tex]2(16) + 2(2) = 36[/tex]
If 32 x 1, Perimeter =
[tex]2(32) + 2(1) = 66[/tex]
Hence, the least perimeter is 24 feet.
Hope this helps. - M
