We have the following functions:
f (x) = 3x + 1
g (x) = x ^ 2-6
We must add both functions.
We have then:
(f + g) (x) = f (x) + g (x)
Substituting we have:
(f + g) (x) = (3x + 1) + (x ^ 2-6)
Then, rewriting:
(f + g) (x) = x ^ 2 + 3x - 5
Answer:
(f + g) (x) = x ^ 2 + 3x - 5
