Answer:
[tex]9(64)\ mm^{2}[/tex]
Step-by-step explanation:
we know that
The area of rectangle is equal to
[tex]A=bh[/tex]
In this problem we have
the larger rectangle
[tex]b=48\ mm[/tex]
[tex]h=12\ mm[/tex]
substitute
[tex]A=48*12=(4*4*3)(4*3)=(3*3)(4*4*4)=9(64)=576\ mm^{2}[/tex]
