emmagrace9907 emmagrace9907

13-04-2018
Chemistry

contestada

How many grams of cucl2 are required to prepare 1250. g of a 1.25% (by mass) cucl2 solution?

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kenmyna kenmyna

22-04-2018

The grams of CuCl2 required to prepare 1250g of 1.25% by mass is calculated as follow

1250 = 100%

what about 1.25%

by cross multiplication

= 1.25 x1250/100 = 15.63 grams

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