contestada



Ninety-three
passengers rode in a train from City A to City B. Tickets for regular coach seats cost
​$122.
Tickets for sleeper cars seats cost
​$284
The receipts for the trip totaled
​$18,960.
How many passengers purchased each type of​ ticket?


The number of coach tickets purchased was ____

The number of sleeper car tickets purchased was ______

Respuesta :

Louli
Answer:
number of coach tickets = 46 tickets
number of sleeper car tickets = 47 tickets

Explanation:
Assume that number of coach tickets is x and that number of sleeper car tickets is y

We are given that:
1- Total number of tickets purchased is 93. This means that:
x + y = 93
This can be rewritten as:
x = 93 - y ............> equation I
2- coach ticket costs $122, sleeper car ticket costs $284 and that the total receipt was for $18960. This means that:
122x + 284y = 18960 ..........> equation II

Substitute with I in II and solve for y as follows:
122x + 284y = 18960
122(93-y) + 284y = 18960
11346 - 122y + 284y = 18960
162y = 7614
y = 7614 / 162
y = 47

Substitute with y in equation I to get x as follows:
x = 03 - y
x = 93 - 47
x = 46 

Hope this helps :)

Otras preguntas