sbrackett727p6s7p5
sbrackett727p6s7p5 sbrackett727p6s7p5
  • 16-04-2018
  • Physics
contestada

help with 26 please:):)

help with 26 please class=

Respuesta :

AL2006
AL2006 AL2006
  • 16-04-2018

(25 watts)·(1 kw/1000 watts)·(1 year)·(365 day/year)·(24 hr/day)·(8¢ / kw-hr)

= (25·1·1·365·24·8) / (1000)   (watts-kw-year-day-hour-¢ / watts-year-day-kWh)

= (1,752,000) / (1000)          ¢

=      $ 17.52
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